2-[5-(2y+3)+3(4y-2)]=0

Solution for 2-[5-(2y+3)+3(4y-2)]=0 equation:

Simplifying
2 + -1[5 + -1(2y + 3) + 3(4y + -2)] = 0

Reorder the terms:
2 + -1[5 + -1(3 + 2y) + 3(4y + -2)] = 0
2 + -1[5 + (3 * -1 + 2y * -1) + 3(4y + -2)] = 0
2 + -1[5 + (-3 + -2y) + 3(4y + -2)] = 0

Reorder the terms:
2 + -1[5 + -3 + -2y + 3(-2 + 4y)] = 0
2 + -1[5 + -3 + -2y + (-2 * 3 + 4y * 3)] = 0
2 + -1[5 + -3 + -2y + (-6 + 12y)] = 0

Reorder the terms:
2 + -1[5 + -3 + -6 + -2y + 12y] = 0

Combine like terms: 5 + -3 = 2
2 + -1[2 + -6 + -2y + 12y] = 0

Combine like terms: 2 + -6 = -4
2 + -1[-4 + -2y + 12y] = 0

Combine like terms: -2y + 12y = 10y
2 + -1[-4 + 10y] = 0
2 + [-4 * -1 + 10y * -1] = 0
2 + [4 + -10y] = 0

Combine like terms: 2 + 4 = 6
6 + -10y = 0

Solving
6 + -10y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -10y = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -10y = 0 + -6
-10y = 0 + -6

Combine like terms: 0 + -6 = -6
-10y = -6

Divide each side by '-10'.
y = 0.6

Simplifying
y = 0.6